leeCode算法--反转字符串

题目：编写一个函数，其作用是将输入的字符串反转过来。输入字符串以字符数组 char[] 的形式给出。不要给另外的数组分配额外的空间，你必须原地修改输入数组、使用 O(1) 的额外空间解决这一问题。你可以假设数组中的所有字符都是 ASCII 码表中的可打印字符。

分析：本地中没什么难度，只是要注意的是不要使用额外空间，空间复杂度是O(1).

var reverseString = function(s) {
    let left = 0
    let right = s.length - 1
    while (left <= right) {
        let temp = s[left]
        s[left] = s[right]
        s[right] = temp
        left++
        right--
    }
    return s
};
reverseString(["h","e","l","l","o"])
//  ["o","l","l","e","h"]
reverseString(["H","a","n","n","a","h"])
//  ["h","a","n","n","a","H"]

That’s all!